2u^2-19u-10=0

Solution for 2u^2-19u-10=0 equation:

Simplifying
2u2 + -19u + -10 = 0

Reorder the terms:
-10 + -19u + 2u2 = 0

Solving
-10 + -19u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-1 + -2u)(10 + -1u) = 0

Subproblem 1
Set the factor '(-1 + -2u)' equal to zero and attempt to solve:

Simplifying
-1 + -2u = 0

Solving
-1 + -2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2u = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2u = 0 + 1
-2u = 0 + 1

Combine like terms: 0 + 1 = 1
-2u = 1

Divide each side by '-2'.
u = -0.5

Simplifying
u = -0.5
Subproblem 2
Set the factor '(10 + -1u)' equal to zero and attempt to solve:

Simplifying
10 + -1u = 0

Solving
10 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1u = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1u = 0 + -10
-1u = 0 + -10

Combine like terms: 0 + -10 = -10
-1u = -10

Divide each side by '-1'.
u = 10

Simplifying
u = 10
Solution
u = {-0.5, 10}